Battle of the Internet Giants,The money and Data

Click above to view the full version [h/t Penny Stocks Lab].
Click the animation to open the full version (via http://pennystocks.la/).

Getting started with BigData and Hadoop

Twitter Sentiment Analysis Using Hadoop and Twitter4j

Hadoop Installation Commands

Nitesh Singh

Running Hadoop on Ubuntu Linux (Single-Node Cluster)

In this tutorial I will describe the required steps for setting up a pseudo-distributed, single-node Hadoop cluster backed by the Hadoop Distributed File System, running on Linux Mint

Facbook makes all profile picture public secretly!!

Yes,You have read it right and yes it is true.
After the launch of Facebook graph there were drastic changes in privacy and thus left many loose ends.
Most of them were fixed but 1 bug remained you could now see anyone's profile picture even if private, you just needed the profile id facebook.com/profile_id

and now type it after graph.facebook.com/profile_id/ this will give you the public profile as json
now type graph.facebook.com/profile_id/picture?width=800

And you can now see the full Resolution private profile picture.
But today i found to cover there tracks facebook made this kind of a feature your profile picture are no longer private.
Facebook did this secretly no user was informed .Also when you upload a picture you still have privacy control to make picture private or public but they are almost fake.Only control they give is if your photo is private comments will be hidden.Who knows what other bugs might exist in facebook.But whatever may happen the people at Facebook will never admit.
So be aware and USE FACEBOOK AT YOUR RISK!! keeping in mind nothing's can say hidden in this age of techonology where even the so called secure https was also hacked!!

Good Luck!

MindSweepers Editorial

Codathon Editorial

PROBLEM LINK:

Practice Contest Author: Nitesh Singh Tester: Nitesh Singh

DIFFICULTY:

EASY-MEDIUM, MATHS

PREREQUISITES:

Coprime,multiplication,Logic

PROBLEM:

given positive integers x1, x2, . . . , xn with gcd(x1, x2, . . . , xn) = 1, compute the largest integer not representable as a non-negative integer linear combination of the xi . This largest integer is sometimes denoted g(x1, . . . , xn). The restriction gcd(x1, x2, . . . , xn) = 1 is necessary for the definition to be meaningful, for otherwise every non-negative integer linear combination is divisible by this gcd in that case answer would be infinity

EXPLANATION:

Given 2 numbers 'a' and 'b' there equation is ax+by,a and b are coprime So all number can be generate just plot ax+by=N find a and and but the condition here was that a and b cannot be negative,in that case only will there be a maximum number that cannot be generated. consider 7,9 7x+9y=k x=(k-9y)/7 multiples of 9 remainder with 7 Numbers not possible to Generate 9 2 2 18 4 4,4+7=11 27 6 6,6+7=13,20 36 1 1,8,15,22,29 45 3 3,10,17,24,31,38 54 5 5,12,19,26,33,40,47 so the biggest not not possible to generate: a*(b-1)+b*-1=a*b-a-b In the above table we see that with multiples of 9 we have generated all possible remainders of 7. so x=(k-9y)/7 here x can always be intere for any value of k because whatever value of k we take it will give a remainder 0 to 6 and we will put y accordingly to compensate that remainder like k=101 k%7=3 so put y=5 x=(101-9*5)/7 =8

AUTHOR'S AND TESTER'S SOLUTIONS:

Solution :c++ Python

Mr IDC and his Love - Editorial

PROBLEM LINK: Practice Contest Author: Rahul Johari Tester: Rahul Johari DIFFICULTY: EASY-MEDIUM, MATHS PREREQUISITES: Division, Summation of series, modular operation PROBLEM: Given a number N and another number MOD, you have to calculate the sum of numbers from 1 to N as: for ( i=1;i<=N;i++ ) sum += i % MOD; EXPLANATION: By the division algorithm, let N = qm+r with 0 ≤ r < m. Consider the sequence (1 % m),(2 % m), ...,(N % m). It looks like this: 1, 2, 3, ..., m − 1, 0, 1, 2, 3, ..., m − 1, 0, ... 1, 2, 3, ..., m − 1, 0, 1, 2, 3, ..., r There are q layers, each with m elements and a final layer with r elements. We know that sum of first N terms is N(N+1)/2 therefore the sum the numbers in each of the q layers is m(m−1)/2 and the sum of the numbers in the last layer is r(r+1)/2. Therefore using this you can easily calculate sum of large values of N also is O(1) complexity. AUTHOR'S AND TESTER'S SOLUTIONS: Solution can be found here. Mr IDC and his Message - Editorial Practice Contest Author: Rahul Johari Tester: Rahul Johari DIFFICULTY: CAKEWALK PREREQUISITES: String handling, typecasting PROBLEM: Mr.IDC wants to send letter to his girlfriend but the problem is he has encrypted the letter and his girlfriend doesn't know how to decrypt. So she needs your help in decrypting the letter using a key K given as input. EXPLANATION: Mr.IDC has replaced each character with a new character (Ci - K) mod 26 where ( i = [ 0,|message| ] ). So you just have to do: l = len(s) ans = [] for i in range(l): ans.append((ord(s[i])-97+k)%26) You will get the final string which is the output.